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If you have 5.2 moles of Na and excess CI2 how many moles of NaCI will be produced 2Na+CI2->2NaCI 10.4 moles NaCI 2.6 moles NaCI 5.2 moles NaCI 2 moles NaCI
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If you have 5.2 moles of Na and excess CI2 how many moles of NaCI will be produced 2Na+CI2->2NaCI

10.4 moles NaCI
2.6 moles NaCI
5.2 moles NaCI
2 moles NaCI

User Vesparun
by
5.4k points

1 Answer

3 votes

Answer:

5.2moles of NaCl

Step-by-step explanation:

The equation for the reaction is:

2Na + Cl2 —> 2NaCl

From the equation,

2moles of Na produced 2moles of NaCl.

Therefore, 5.2moles of Na will also produce 5.2moles of NaCl

User Troy Sabin
by
6.2k points
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