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A brown bear runs at a speed of 9.0\,\dfrac{\text m}{\text s}9.0 s m ​ 9, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction with 23,000\,\text J23,000J23, comma, 000, start text, J, end text of kinetic energy. What is the bear’s mass?

User Zion
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2 Answers

5 votes

Answer:

m = 0.5679 Kg

Step-by-step explanation:

Given

v = 9 m/s

K = 23 KJ

m = ?

We apply the equation

K = 0.5*m*v² ⇒ m = 2*K/v²

⇒ m = 2*23000 J/(9 m/s)² = 567,9 Kg

User Kanan Farzali
by
4.9k points
4 votes

Step-by-step explanation:

Below is an attachment containing the solution.

A brown bear runs at a speed of 9.0\,\dfrac{\text m}{\text s}9.0 s m ​ 9, point, 0, start-example-1
User Spatialist
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4.3k points