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If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x?

2 Answers

2 votes

Answer:

the answer is 3

Explanation:

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User Veryreverie
by
6.6k points
4 votes

Answer:

x=3

Explanation:

We want to solve the equation:


5 + 20 * {2}^(2 - 3x) = 10 * {2}^( - 2x) + 5

We subtract 5 from both sides to get:


20 * {2}^(2 - 3x) = 10 * {2}^( - 2x)

We divide both sides by 10 to get:


2 * {2}^(2 - 3x) = {2}^( - 2x)


{2}^(1) * {2}^(2 - 3x) = {2}^( - 2x)

We now simplify LHS using the product rule:


{2}^(1 + 2 - 3x) = {2}^( - 2x)

Since the base is the same on both sides, we equate the exponents to get:


1 + 2 - 3x = - 2x


1 + 2 = - 2x + 3x


x = 3

User Drgmak
by
7.0k points
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