Answer:
1. P(both Professors funded)=0.155
2. P(at least one Professor funded)=0.715
3. P(Jane funded but Joe not funded)=0.465
4. P(Professor Jane is funded but Professor Joe is not/at least one Professor funded)=0.6503
Explanation:
P(Professor Jane funded)=P(F1)=0.62
P(Professor Joe funded)=P(F2)=0.25
P(F1')=1-P(F1)=1-0.62=0.38
P(F2')=1-P(F2)=1-0.25=0.75
1.
P(both Professors funded)=P(F1∩F2)
P(both Professors funded)=P(F1)*P(F2)
P(both Professors funded)=0.62*0.25
P(both Professors funded)=0.155
2.
P(at least one Professor funded)=P(F1∪F2)
P(at least one Professor funded)=P(F1)+P(F2)-P(F1∩F2)
P(at least one Professor funded)=0.62+0.25-0.155
P(at least one Professor funded)=0.87-0.155
P(at least one Professor funded)=0.715
3.
P(Jane funded but Joe not funded)=P(F1∩F2')
P(Jane funded but Joe not funded)=P(F1)*P(F2')
P(Jane funded but Joe not funded)=0.62*0.75
P(Jane funded but Joe not funded)=0.465
4.
P(Professor Jane is funded but Professor Joe is not/at least one Professor funded)=P(F1∩F2')/P(F1∪F2)
=P(F1∩F2')∩(F1∪F2)/P(F1∪F2)
=P(F1∩F2')/P(F1∪F2)
P(Professor Jane is funded but Professor Joe is not/at least one Professor funded)=0.465/0.715
P(Professor Jane is funded but Professor Joe is not/at least one Professor funded)=0.6503