Answer:
The y-intercept is the point (0,-8)
see the attached figure
Explanation:
we have
![f(x)=x^(2)-2x-8](https://img.qammunity.org/2021/formulas/mathematics/middle-school/dmbisnypgowny47ztrife870iocngderi2.png)
we know that
The y-intercept is the value of the function f(x) when the value of x is equal to zero
so
For x=0
![f(x)=0^(2)-2(0)-8\\f(x)=-8](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vjb9om79wqdohejmgduc0d49yj30qj4hc5.png)
therefore
The y-intercept is the point (0,-8)
see the attached figure to better understand the problem