Question

Write a program that tells what coins to give out for any amount of change from 1

cent to 99 cents. For example, if the amount is 86 cents, the output would be

something like the following:

86 cents can be given as:

3 quarter(s), 1 dime(s), and 1 penny (pennies)

Use coin denominations of 25 cents (quarters), 10 cents (dimes), and 1 cent

(pennies). Do not use nickel and half-dollar coins. Your program will use the

following function (possibly among others):

Void computeCoin( int coinValue, int& number, int& amountLeft );

// Precondition: 0
// Postcondition: number has been set equal to the maximum

// number of coings of denomination coinValue cents that

// can be obtained from amountLeft cents. amountLeft has

// been decreased by the value of the coins, that is,

// decreased by number*coinValue.

For example, suppose the value of the variable amountLeftis 86. Then, after the

following call, the value of numberwill be 3 and the value of amountLeftwill be 11

(because if you take three quarters from 86 cents, that leaves 11 cents):

computeCoins(25, number, amountLeft);

Testing your program:

Be sure to test your program with various values to ensure it provides the correct

output before submitting to get full credit. For extra credit, have your program only

accept proper input values (1 to 99). If the user attempts to enter an invalid

number, your program should output an error message and repeat the input

process until it receives an appropriate value. (Hint: use a while or do-while loop.)

Answer 1

#include<iostream>

using namespace std;

void computeCoin(int coinValue, int& number, int& amountLeft)

{

number = amountLeft / coinValue;

amountLeft = amountLeft % coinValue;

}

int main()

{

int cents;

int number;

char ch;

do

{

cout << "Enter no of cents. :";

cin >> cents;

while(cents<1 || cents >99)

{

cout << "Invalid cents entered. Re-Enter no of cents. :";

cin >> cents;

}

cout << cents <<" can be given as ";

computeCoin(25,number,cents);

if(number)

cout << number << " quarters ";

computeCoin(10,number,cents);

if(number)

cout << number << " dimes and ";

cout << cents << " penny"<<endl;

cout<< "do u want to continue enter y or n :";

cin >> ch;

}while(ch=='y');

return 0;

}

Step-by-step explanation: