Question

Calculate the potential difference two charges when 6 joules of energy is needed to bring a charge of 0.01C close to the other charge.

Answer 1

Answer: 1200 volts

Step-by-step explanation:

Given that

W = 1/2 × QV

Where q is the charge in coulombs = 0.01 C

W = energy in the capacitor

V = potential difference in volts

Hence,

W = 6 = 1/2 × 0.01 × V

6×2 = 0.01 ×V

12 = 0.01 V

V = 12÷ 0.01

V = 1200 volts