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4 votes
When you blow across the top of a

soda bottle, it acts like a closed pipe
with a fundamental frequency of
495 Hz. If you pour 0.030 m of water
into the bottle, shortening the air cavity,
what is the new fundamental frequency?
(Hint: Find the original length.)
(Speed of sound = 343 m/s)
(Unit = Hz)​

User Mmachine
by
6.1k points

2 Answers

5 votes

Answer:

598.7 Hz

Step-by-step explanation:

User OlduwanSteve
by
6.0k points
5 votes

Answer:

The new fundamental frequency will be 598.7Hz.

Step-by-step explanation:

The fundamental wavelength of the sound waves in the soda bottle is given by the equation


\lambda = (v)/(f)

where
v is the speed of sound, and
f is the frequency. Since
f = 495Hz and
v = 343m/s, we have


\lambda = (343m/s)/(495Hz)


\boxed{\lambda = 0.693m.}

Because it is a fundamental wavelength, the length
L of the soda can must be


L = (\lambda)/(4)


L = (0.693)/(4)


\boxed{L = 0.173m}

The length of the soda bottle is 0.173 meters.

Now, if we pour 0.030 m of water, the new length of the air cavity becomes
L_(new)=0.173m-0.03m


L_(new) = 0.143m

Therefore, the new fundamental wavelength will be


\lambda_(new) = 4L_(new)


\lambda_(new) = 0.573m,

which is a frequency of


f_(new) = (343m/s)/(0.573m)


\boxed{ f_(new) = 598.7 Hz.}

Thus, the new fundamental frequency is 598.7Hz.

User Jordan Stewart
by
6.3k points