Question

A truck carrying a 65.4-kg crate accelerates from rest to [07]____________________ km/hr on a flat horizontal surface in 15.2 seconds. The acceleration was not constant. How much work (J) was done on the crate by the truck?

Answer 1

The work done on the crate by the truck is 9472.54 J.

Step-by-step explanation:

Given that,

Mass of the truck, m = 65.4 kg

Initially, the object is at rest, u = 0

Final speed of the truck, v = 61.3 km /h = 17.02 m/s

m/s

Time, t = 15.2 s

We need to find the work done on the crate by the truck. The work done is equal to the change in kinetic energy of the truck as :

`W=\Delta K`

`W=K_f-K_i`

`W=K_f-0`

`W=(1)/(2)mv^2`

`W=(1)/(2)* 65.4* (17.02)^2`

`W=9472.54\ J`

So, the work done on the crate by the truck is 9472.54 J. Hence, this is the required solution.