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D/dx 0∫x √1+a^3 da i need help badly

User Jurgy
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1 Answer

6 votes

Looks like the derivative of an integral,


\displaystyle(\mathrm d)/(\mathrm dx)\int_0^x√(1+a^3)\,\mathrm da

Recall the fundamental theorem of calculus:


\displaystyle(\mathrm d)/(\mathrm dx)\int_c^(f(x))g(u)\,\mathrm du=g(f(x))f'(x)

where
c is some constant.

Directly applying the theorem here gives the derivative,


\boxed{√(1+x^3)}

User Mero
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