Question

A 2.00 C charge moves from a +50.0 V equipotential line to a +40.0 V equipotential line. What is the change in the electric potential energy of the charge field system?

Answer 1

Step-by-step explanation:

Potential on first line, V1 = 50 V

Potential on second line, V2 = 40 V

Charge, q = 2 C

Change in potential, ΔV = V1 - V2 = 50 - 40 = 10 V

Potential energy is given by

U = q x ΔV

U = 2 x 10

U = 20 J

Answer 2

Step-by-step explanation:

Change in electric potential energy

= charge x potential difference

= 2 x ( 50 - 40)

= 20 J

Potential will be decreased by this amount.