Question

What is the solubility of calcium sulfate (CaSO4) in 0.30 M aqueous sodium sulfate (Na2SO4)? (Ksp of calcium sulfate = 2.0 x 10^-5

Answer 1

B. 6.7 x 10 -5 M

Step-by-step explanation:

Answer 2

Therefore the solubility of CaSO₄ in Na₂SO₄ is =907.12 g/L.

Step-by-step explanation:

CaSO₄ → Ca²⁺ + SO₄²⁻

Initially 0 0 0

Finally s s s

`K_(sp)=[Ca^(2+)][SO_4^(2-)]`........(1)

Na₂SO₄ → Na²⁺ + SO₄²⁻

Given, the concentration of Na₂SO₄ is 0.30 M .

Then [Na²⁺] = [SO₄²⁻] = 0.30

`K_(sp)=2.0* 10^(-5)`

Putting the value of
`K_(sp)` and [SO₄²⁻] in equation (1)

`2.0* 10^(-5)= [Ca^(2+)]0.30`

`\Rightarrow [Ca^(2+)]=(2.0* 10^(-5))/(0.30)`

= 6.67×10⁻⁵

The atomic mass of CaSO₄ is 136 g/mol

Therefore the solubility of CaSO₄ in Na₂SO₄ is = (6.67×10⁻⁵×136)g/L

=907.12 g/L