Question

A 6 oz paper cup is shaped like a cone with a diameter of 4 inches. How many ounces of water will a plastic cylindrical cup with a diameter of 4 inches hold if it is the same height as the paper cup?

Answer 1

its b according to geogebra.org

Explanation:

Answer 2

The plastic cylindrical cup will hold 17.96 ounces of water.

Explanation:

Given:

A 6 oz paper cup is shaped like a cone with a diameter of 4 inches.

Now, to find ounces of water will a plastic cylindrical cup with a diameter of 4 inches hold if it is the same height as the paper cup.

Volume of cone = 6 oz.

Diameter = 4 inches.

So, radius (r) =
`(Diameter)/(2) =(4)/(2) =2\ inches.`

Taking the value
`\pi` = 3.14.

Now, to get the height (h) we put formula:

`Volume=\pi r^2(h)/(3)`

`Volume=3.14* 2^2* (h)/(3)`

`6=3.14* 4* (h)/(3)`

Multiplying both sides by 3 we get:

`18=12.56h`

Dividing both sides by 12.56 we get:

`1.43=h`

`h=1.43\ inches.`

Now, to get the volume of cylindrical cup.

As, given it is the same height as the paper cup.

Height (h) = 1.43 inches.

Diameter = 4 inches.

Radius (r) =
`(Diameter)/(2) =(4)/(2) =2\ inches.`

So, we put formula to get the ounces of water a plastic cylindrical cup will hold:

`Volume =\pi r^2h`

`Volume=3.14* 2^2* 1.43`

`Volume=3.14* 4* 1.43`

`Volume=17.96\ oz.`

Therefore, the plastic cylindrical cup will hold 17.96 ounces of water.