Question

Ben starts walking along a path at 3 3 mi/h. One and a half hours after Ben leaves, his sister Amanda begins jogging along the same path at 6 6 mi/h. How long will it be before Amanda catches up to Ben?

Answer 1

3 hours

Step-by-step explanation:

Given:

- The speed of Ben v_b = 3 mi/h

- The speed of Amanda v_a = 6 mi/h

- The total time taken to cover distance(d) by ben = t_b

Find:

How long will it be before Amanda catches up to Ben?

Solution:

- The distance d traveled by Ben:

d = v_b*t_b

d = 3*t_b

- The distance d traveled by Amanda:

d = v_a*t_a

d = 6*t_a

- Equate the distance as when they meet:

3*t_b = 6*t_a

- Where ,

t_b = t_a + 1.5

t_a = t_b - 1.5

- Substitute the time relationship in distance relationship:

3*t_b = 6*(t_b - 1.5)

3*t_b = 6*1.5

t_b = 2*1.5 = 3 h

- Hence, It would take 3 hours since Ben starts walking that amanda catches up.