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A random variable X that has probability mass function (pmf) given by p(x) = 1/(b-a+1) over the range Rx = [a, a+1, a+2, …, b] is said to have a discrete uniformed distribution. Calculate the following statistics values: a) What is the mean of this distribution? b) What is the variance of this distribution (you can use the result from the previous problem)?

User Reox
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2 Answers

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Final answer:

The mean of a discrete uniform distribution is calculated as (a + b) / 2, and the variance is found using the formula ((b - a + 1)² - 1) / 12.

Step-by-step explanation:

Calculating Mean and Variance of a Discrete Uniform Distribution

The mean (expected value) of a discrete uniform distribution for a random variable X can be calculated using the formula μ = (a + b) / 2, which is derived from the sum of the smallest number in the range (a) and the largest number (b), divided by 2. To find the variance, we use σ² = (b - a + 1)² - 1) / 12. The variance formula comes from the range (b - a + 1), which indicates the number of possible values that X can take on, squared and then subtracting 1, finally divided by 12.

To provide an example, if a = 3 and b = 6 for the discrete random variable X, the mean would be calculated as μ = (3 + 6) / 2 = 4.5. The variance would be σ² = ((6 - 3 + 1)² - 1) / 12 = (16 - 1) / 12 = 15 / 12 = 1.25.

User Kenneth Li
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3 votes

Answer:

Step-by-step explanation:

See the attached picture for detailed explanation.

A random variable X that has probability mass function (pmf) given by p(x) = 1/(b-example-1
A random variable X that has probability mass function (pmf) given by p(x) = 1/(b-example-2
A random variable X that has probability mass function (pmf) given by p(x) = 1/(b-example-3
User Steve Pallen
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