Question

1. In the cone below, the radius is 6 meters and the height is 8 meters.

A) Find the exact value of the volume of the cone.
formula
Pug in #s V =
solution with a label V =

B) Find the approximate value of the volume of the cone rounded to the
nearest tenth.

formula V =
Pug in #s V =
solution with a label V =

2. Find the volume of the cylinder pictured below. Use 3.14 for pi. Give your answer rounded to the nearest tenth.

formula V =
Pug in #s V =
solution with a label V =

3. Find the volume of the sphere pictured below. The sphere has a radius of 20 cm. Use 3.14 for pi. Give your
answer rounded to the nearest tenth.

formula V =
Pug in #s V =
solution with a label V =


* I REALLY NEED THE ANSWERS TO THESE 3 QUESTIONS BY 8:00 PM TONIGHT!! PLEASE PLEASE PLEASE HELP ME IF YOU CAN!! THANK YOUUUU!!!*

Answer 1

Question 1.

• a)
  `V=96\pi m^3`

• b)
  `V=301.4m^3`

Question 2:

`V=1,648.5ft^3`

Question 3:

`V=1,674.7cm^3`

Step-by-step explanation:

Question 1. In the cone below, the radius is 6 meters and the height is 8 meters.

A) Find the exact value of the volume of the cone.

Formula:

`V=(1)/(3)\pi r^2h`

Plug in r = 6m, and h = 8m

`V=(1)/(3)\pi (6m)^2(8m)\\\\\\ V=(1)/(3)(36)(8)\pi m^3`

Solution:

`V=96\pi m^3`

B) Find the approximate value of the volume of the cone rounded to the nearest tenth.

Substitute π with its approximate value 3.14

`V=96(3.14)m^3\\\\V=301.4m^3`

Question 2. Find the volume of the cylinder pictured below. Use 3.14 for pi. Give your answer rounded to the nearest tenth.

Formula

`V=\pi* ((diameter)/(2))^2* height`

Plug in diameter = 10 ft, height = 21, and π = 3.14

`V=3.14* ((10)/(2))^2* 21ft\\\\V=3.14* 25ft* 21ft`

Solution:

`V=1,648.5ft^3`

Question 3. Find the volume of the sphere pictured below. The sphere has a radius of 20 cm. Use 3.14 for pi. Give your answer rounded to the nearest tenth.

Formula

`V==(4)/(3)\pi r^3`

Plug in r = 20cm, and π = 3.14

`V=(4)/(3)* 3.14* (20cm)^3`

Solution:

`V=1,674.7cm^3`