Question

-2x^2+bx -5 Determine the b-value that would ensure the function has two real root.

Answer 1

• No solution

Explanation:

Given is the quadratic function

• y = -2x² + bx - 5

In order to have two real roots the discriminant should be posivive

• D = - b² - 4ac
• D = - b² - 4(-2)(-5) = - b² - 40

We need D > 0

• -b² - 40 > 0
• b² + 40 < 0
• b² < - 40

There is no solution as b² is never negative