Question

Speakers A and B are vibrating in phase. They are directly facing each other, are 6.69 m apart, and are each playing a 75.0-Hz tone. The speed of sound is 343 m/s. What is the distance from speaker A to the first point on the line between the speakers where constructive interference occurs?

Answer 1

3.117 m

Step-by-step explanation:

Given that:

the distance of separation between speaker A and speaker B (L) = 6.69 m

Frequency (F) = 750 -Hz tone

Velocity of speed of sound = 343 m/s

The distance from Speaker A to the first point (L₁) on the line can be calculated by using the formula:

`L_1=(L-A)/(2)`

where A =
`(Velocity ofthe sound (V))/(Frequency (F))`

we have:

`L_1=(L-(V)/(F) )/(2)`

`L_1=(6.69-(343)/(750) )/(2)`

`L_1=(6.69-0.457 )/(2)`

`L_1=(6.233 )/(2)`

`L_1= 3.1165 m`

`L_1=3.117 m`

∴ the distance from speaker A to the first point on the line between the speakers where constructive interference occurs = 3.117 m