Answer:
7.07volts
Step-by-step explanation:
Power generated by a load or resistor in an electric circuit is represented as P = IV... (1) where;
P is the power measured in watts (W)
I is the current flowing through the resistor in amperes
V is the maximum voltage passed across the circuit in volts
According to ohms law V = IR; I = V/R... (2)
Substituting equation 2 into 1
P = IV
P = V/R×V
P = V²/R
Given the power rating = 1/4w
Resistor = 200ohms
V² = PR
V² = 200×1/4
V² = 50
V = √50
V = 7.07volts
Therefore the maximum voltage that can safely be connected across it is 7.07Volts.