Question

solution is 2.41 molal toluene (C 7H 8, 92 g/mol) in benzene (C 6H 6, 78 g/mol); i.e. consider toluene the solute, benzene the solvent. What is the molarity? The density of the solution is 0.876 g/cm 3.

Answer 1

Answer : The molarity of solution is, 1.73 mole/L

Explanation :

The relation between the molarity, molality and the density of the solution is,

where,

`d=M[(1)/(m)+(M_b)/(1000)]`

d = density of solution =
`0.876g/cm^3=0.876g/mL`

m = molality of solution = 2.41 mol/kg

M = molarity of solution = ?

`M_b` = molar mass of solute (toluene) = 92 g/mole

Now put all the given values in the above formula, we get the molality of the solution.

`0.876g/ml=M* [(1)/(2.41mol/kg)+(92g/mole)/(1000)]`

`M=1.73mol/L`

Therefore, the molarity of solution is, 1.73 mole/L