Question

Ask Your Teacher A coil has an inductance of 3.00 mH, and the current in it changes from 0.200 A to 1.50 A in a time interval of 0.200 s. Find the magnitude of the average induced emf in the coil during this time interval.

Answer 1

Magnitude of the average induced emf in the coil
`= 0.0195` Volts

Step-by-step explanation:

Induced emf in a coil with current flowing through it is can be calculated using the relation given below

`emf = -L(dI)/(dt)` ------------ Equation (1)

Where "L" represents the inductance in H

dI represents the change in current in Ampere

and dt represents the change in time or time period for which the current is flowing in seconds

Given

`L = 3.00` mH
`= 3 * 10^ {-3}` H

`I_0 = 0.200` Ampere

`I_t = 1.50` Ampere

`t = 0.200` seconds

Substituting the given values in equation (1) we get -

`emf = - (3 * 10^(-3)) * (1.500 - 0.200)/(0.200) \\emf = 0.0195`