Question

A 7.80-g bullet moving at 570 m/s strikes the hand of a superhero, causing the hand to move 4.40 cm in the direction of the bullet's velocity before stopping.

Answer 1

The average force is 28797.95 N.

Step-by-step explanation:

Given that,

Mass of bullet = 7.80 g

Speed = 570 m/s

Distance = 4.40 cm

Suppose Use work and energy considerations to find the average force that stops the bullet.

We need to calculate the average force

Using work energy theorem

`W=\Delta K.E`

`F\cdot s=(1)/(2)mv^2`

Put the value into the formula

`F* 4.40*10^(-2)=(1)/(2)*7.80*10^(-3)*(570)^2`

`F=((1)/(2)*7.80*10^(-3)*(570)^2)/(4.40*10^(-2))`

`F=28797.95\ N`

Hence, The average force is 28797.95 N.