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You throw a ball of mass 190 g upward. When the ball is 2 m above the ground, headed upward (the initial state), its speed is 18 m/s. Later, when the ball is again 2 m above the ground, this time headed downward (the final state), its speed is 18 m/s. What is the change in the kinetic energy of the ball from initial to final state?

User AndyV
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1 Answer

3 votes

Answer:

Change in Kinetic energy is zero

Step-by-step explanation:

Given

Mass of Ball
= 190 grams
= 0.19 Kg

Speed at height of
2 m
= 18 (m)/(s)

Kinetic energy is equal to


(1)/(2) mv^2

Where M is the mass of the object and v is the velocity of the object

Change in kinetic energy
= KE_2 - KE_1

Substituting the given values we get -

Change in kinetic energy
= (1)/(2) m_1v_1^2 - (1)/(2) m_2v_2^2

Change in kinetic energy
= (1)/(2) 0.19*18^2 - (1)/(2) 0.19*18^2\\= 30.78 - 30.78\\= 0

Hence, the change in Kinetic energy is zero

User Dradd
by
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