Question

A concert loudspeaker suspended high off the ground emits 28.0 W of sound power. A small microphone with a 0.700 cm2 area is 55.0 m from the speaker. What is the sound intensity at the position of the microphone?

Answer 1

Step-by-step explanation:

It is known that wave intensity is the power to area ratio.

Mathematically, I =
`(P)/(A)`

As it is given that power is 28.0 W and area is
`7 * 10^(-5) m^(2)`.

Therefore, sound intensity will be calculated as follows.

I =
`(P)/(A)`

=
`(28.0 W)/(4 * 3.14 * 7 * 10^(-5) m^(2))`

=
`0.318 * 10^(5) W/m^(2)`

or, =
`3.18 * 10^(4) W/m^(2)`

Thus, we can conclude that sound intensity at the position of the microphone is
`3.18 * 10^(4) W/m^(2)`.