Question

A stone is thrown downward with a speed of 8 m/s from a height of 14 m. (acceleration due to gravity: 10 m/s2) What is the speed (in m/s) of the stone just before it hits the ground

Answer 1

The speed of the stone just before it hits the ground is 18.54 m/s

Step-by-step explanation:

Given that,

Initial speed of the stone, u = 8 m/s

The stone is thrown downward from a height of 14 m

We need to find the speed of the stone just before it hits the ground. It can be calculated using third equation of motion as :

`v^2-u^2=2ah`

v is the speed of the stone just before it hits the ground

`v^2=2ah+u^2`

`v^2=2* 10* 14+(8)^2`

v = 18.54 m/s

So, the speed of the stone just before it hits the ground is 18.54 m/s. Hence, this is the required solution.