Question

In a wire with a 1.35 1.35 mm2 cross-sectional area, 5.41 × 10 20 5.41×1020 electrons flow past any point during 2.19 2.19 s. What is the current in the wire?

Answer 1

The current in the wire = 39.53 A.

Step-by-step explanation:

The given cross -sectional area of the wire = 1.35
`mm^2`.

The number of electrons flowing in the wire at any point is

= 5.41
`* 10^(20)` electrons.

The charge of an electron is known to be =
`1.6 * 10^(-19) \hspace{0.1cm} Coulombs`

The electronics flow across the wire for a time of, t = 2.19 seconds.

The current in the wire = (number of electrons) ×
`\frac{charge \hspace{0.1cm} of \hspace{0.1cm} an \hspace{0.1cm} electron}{time}`

= 5.41
`* 10^(20)` ×
`(1.6 * 10^(-19))/(2.19)`

= 39.53 A.

The formula for current is actually, i =
`(dq)/(dt)` .

The (number of electrons )×(charge of an electron) will equal the total charge flowing through the wire in the given time = 2.19 seconds.

The current in the wire = 39.53 A.