Question

An infinite line of charge with linear density λ1 = -7.8μC/m is positioned along the axis of a thick conducting cylindrical shell of inner radius a = 2.9 cm and outer radius b = 5.3 cm and infinite length. The conducting cylindrical shell is uniformly charged with a linear charge density λ 2 = 5.4 μC/m. 1)What is Ex(P), the electric field at point P, located at (x,y) = (-10.1 cm, 0 cm) ?

Answer 1

The electric field at point P is
`4.27*10^(5)\ N/C`

Step-by-step explanation:

Given that,

Linear density
`\lambda_(1)=-7.8\ \mu C/m`

Linear density
`\lambda_(2)=5.4\ \mu C/m`

Inner radius a=2.9 cm

Outer radius = 5.3 cm

We need to calculate the electric field at point P

Using formula of electric field

`E_(x)=((\lambda_(1)+\lambda_(2)))/(2\pi\epsilon_(0)d)`

Put the value into the formula

`E_(x)=((-7.8+5.4)*10^(-6))/(2\pi*8.85*10^(-12)*(-0.101))`

`E_(x)=4.27*10^(5)\ N/C`

Hence, The electric field at point P is
`4.27*10^(5)\ N/C`