Answer: The zeros are x = 1 /4 or
x = -1
Explanation:
The given equation is expressed as
y = 4x² + 3x - 1
To determine the zeros of the quadratic equation, we would equate it to zero first. It becomes
4x² + 3x - 1 = 0
We would apply the method of factorization. We would find two numbers such that their sum or difference is 3x and their product is - 4x². The two numbers are 4x and
- x. Therefore,
4x² + 4x - x - 1 = 0
4x(x + 1) - 1(x + 1) = 0
4x - 1 = 0 or x + 1 = 0
x = 1 /4 or x = -1