Question

The circumference of the inner circle is 66 ft. The distance between the inner circle and the outer circle is 44 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner​ circle? Use 22/7 for PI.

Answer 1

276 4/7 ft

Explanation:

Let r1 represent the radius of the inner circle. Then its circumference in feet is ...

C = 2πr

66 = 2π(r1)

If the radius of the outer circle is (r1 +44), then its circumference is ...

C = 2π(r1 +44) = 2π(r1) +2π(44)

C = 66 +88π

Then the difference in the circumferences is ...

(66 +88π) - (66) = 88π

Using the given value of π, the difference in circumferences is ...

(88 ft)(22/7) = 1936/7 ft = 276 4/7 ft