Answer:
The 5 hour growth/decay factor for the number of milli-grams of caffeine in Alan's body is 0.4759
Explanation:
We are given the following in the question:
Caffeine in Alan's body decreases exponentially.
10 hour delay factor = 0.2265
We have to calculate 5 hour delay factor of Alan's body.
Let b be 1 hour delay factor.
Then, we can write
![b^(10) = 0.2265\\\Rightarrow b = (0.2265)^{(1)/(10)}\\\Rightarrow b \approx 0.8619](https://img.qammunity.org/2021/formulas/mathematics/college/gbv7z32jiq6ptia5pug4mhlzy9c7gxf646.png)
To calculate 5-hour growth/decay factor:
![=(b)^5\\=(0.8619)^5\\=0.4759](https://img.qammunity.org/2021/formulas/mathematics/college/vwb2mew6mocwccngsr2vgrwssm6e9jgu5j.png)
Thus, the 5 hour growth/decay factor for the number of milli-grams of caffeine in Alan's body is 0.4759