Answer:
0.84
Explanation:
Let the probability that a city bus is ready for service when needed is represented as P(ready)=77%=0.77
Let the probability that a city bus is ready for service and has a working radio be represented as P(ready and radio)=65%=0.65
probabilty that it has a working radio given that it is ready for service =
P(radio and ready)=P(ready and radio) ÷ P(ready)
=0.65÷0.77=0.84416
≈0.84 to the nearest tenth