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Find θ, 0° ≤ θ < 360°, given the following information. cos θ = -(√(3) )/(2) and θ in QII θ = ________°
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2 votes
Find θ, 0° ≤ θ < 360°, given the following information.

cos θ =
-(√(3) )/(2) and θ in QII
θ = ________°

User Rita
by
8.5k points

1 Answer

5 votes

Answer:

Θ = 150°

Explanation:

Given

cosΘ = -
(√(3) )/(2), then

Θ =
cos^(-1) ( -
(√(3) )/(2) ) = 150° ← angle in second quadrant

User Jester
by
8.6k points
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