Question

How many moles of SnCl2 will be produced if 85.3 g of FeCl3 is reacted with an excess of Sn for the following reaction:2 FeCl3(s) + 3 Sn(s) → 3 SnCl2(s) + 2 Fe(s)

Answer 1

The answer to your question is 0.79 moles of SnCl₂

Step-by-step explanation:

Data

moles of SnCl₂ = ?

mass of FeCl₃ = 85.3 g

excess Sn

Balanced chemical reaction

2 FeCl₃ + 3 Sn ⇒ 3 SnCl₂ + 2 Fe

Process

1.- Convert the mass of FeCl₃ to moles

Molar mass of FeCl₃ = 56 + (35.5 x 3)

= 56 + 106.5

= 162.5 g

Use proportions to find the moles of FeCl₃

162.5 g -------------------- 1 mol

85.3 g ------------------- x

x = (85.3 x 1) / 162.5

x = 0.525 moles

2.- Find the number of moles SnCl₂

2 moles of FeCl₃ ----------------- 3 moles of SnCl₂

0.525 moles ----------------- x

x = (0.525 x 3) / 2

x = 0.79 moles of SnCl₂