Question

a cart is initially moving at 0.5 m/s along a track. The cart comes to rest after traveling I m. The experiment is repeated on the same track, but now the cart is initially moving at I m/s. How far does the cart travel before coming to rest?

Answer 1

Step-by-step explanation:

Below is an attachment containing the solution.

Answer 2

4m

Step-by-step explanation:

Using the kinematic equation;

For the first stage when the car is initially moving at 0.5m/s

definitely u = 0.5 m/s and v = 0

The cart comes to rest after traveling I m, ∴ (s) = 1m

the acceleration of the car can be expressed by applying the kinematic equation:

`v^2-u^2=2as`

making "a" the subject of the formula; we have:

`a = (v^2-u^2)/(2s)`

`a= (0-(0.5 m/s)^2)/(2(1m))`

a = 0.125 m/s²

The experiment is repeated on the same track, but now the cart is initially moving at I m/s

i.e v = 1 m/s and u=0

`S=(v^2-u^2)/(2a)`

`S= ((1m/s)^2-0)/(2(0.125m/s^2))`

S = 4 m

∴ the cart traveled 4m before coming to rest.