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The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an is the number of teams competing and n is the round. There are 16 teams remaining in round 4 and 4 teams in round 6.

The explicit rule for the geometric sequence is:

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Answer:

The geometric series is given by:


a_n = 128\bigg((1)/(2)\bigg)^(n-1)

Explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first term and r be the common ratio.

The
n^(th) term of a geometric sequence is given by:


a_n = ar^(n-1)

There are 16 teams remaining in round 4 and 4 teams in round 6.

Thus, we can write:


a_4 = 16 = ar^3\\a_6 = 4 = ar^5

Dividing the two equations, we get,


(16)/(4)=(ar^3)/(ar^5)\\\\4=(1)/(r^2)\\r^2=(1)/(4)\\\\r = (1)/(2)

Putting value of r in he equation we get:


16=a((1)/(2))^2\\\\a = 16* 2^3\\a = 128

Thus, the geometric sequence can be written as:


a_n = 128\bigg((1)/(2)\bigg)^(n-1)

User Joren Van Severen
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