Question

What was the initial pressure of a 4.5ml container if the new volume is 0.09L with a pressure of 466mmHg?

The answer is 9320mmHg or 12.26atm. I need help with the work though.

Answer 1

The answer to your question is P₁ = 9320 mmHg

Step-by-step explanation:

Data

Pressure 1 = x

Volume 1 = 4.5 ml

Pressure 2 = 466 mmHg

Volume 2= 0.09 L

Formula

To solve this problem use Boyle's law

P₁V₁ = P₂V₂

Solve for P₁

P₁ = P₂V₂ / V₁

Substitution

P₁ = (466 x 90) / 4.5

Simplification

P₁ = 41940 / 4.5

Result

P₁ = 9320 mmHg