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When we drive our car at 100 feet per second​ [ft/s], we measure an aerodynamic force​ (called drag) of 65 ​pounds-force ​[lb Subscript f ​] that opposes the motion of the car. How much horsepower​ [hp] is required to overcome this​ drag?

User DJJ
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1 Answer

5 votes

Answer:

Power = 11.81[hp]

Step-by-step explanation:

We remember that the power is equal to the product of speed by force, in this way we have:

P = F * V

where:

F = force [N]

V = velocity [m/s]

we must consider the following relationship


1 [hp] = 550 [lbf*(ft)/(s)]\\therefore:\\(65*100) = P\\P = 6500 [lbf*(ft)/(s) ]\\1[hp] = 550 [lbf*(ft)/(s) ]\\x = 6500 [lbf*(ft)/(s) ]\\x = 11.8 [hp]

User Laure
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