Question

Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.92×1016Cl− ions arrive at the positive electrode. Part A What is the current passing between the electrodes?

Answer 1

Answer : The current passing between the electrodes is,
`1.056* 10^(-2)A`

Explanation :

First we have to calculate the charge of sodium ion.

`q=ne`

where,

q = charge of sodium ion

n = number of sodium ion =
`2.68* 10^(16)`

e = charge on electron =
`1.6* 10^(-19)C`

Now put all the given values in the above formula, we get:

`q=(2.68* 10^(16))* (1.6* 10^(-19)C)=4.288* 10^(-3)C`

Now we have to calculate the charge of chlorine ion.

`q'=ne`

where,

q' = charge of chlorine ion

n = number of chlorine ion =
`3.92* 10^(16)`

e = charge on electron =
`1.6* 10^(-19)C`

Now put all the given values in the above formula, we get:

`q'=(3.92* 10^(16))* (1.6* 10^(-19)C)=6.272* 10^(-3)C`

Now we have to calculate the current passing between the electrodes.

`I=(q)/(t)+(q')/(t)`

`I=(4.288* 10^(-3))/(1.00)+(6.272* 10^(-3))/(1.00)`

`I=1.056* 10^(-2)A`

Thus, the current passing between the electrodes is,
`1.056* 10^(-2)A`