Question

What is the empirical formula of a substance that contains 2.64 g of c

Answer 1

`CH_2O_2`

Step-by-step explanation:

What is the empirical formula of a substance that contains 2.64 g of C, 0.444 g of H, and 7.04 g of O?

First, find the number of mole of each element:

moles = mass/molar mass.

moles C = 2.64 g / 12.011 = 0.220

moles H = 0.444 g/ 1.008 = 0.440

moles = 7.04 g / 15.999 = 0.440

Divide each mole by the smallest mole

C = 0.220/0.220 = 1

H = 0.440/0.220 = 2

O = 0.440/0.220 = 2

Hence, the empirical formular is
`CH_2O_2`