Question

Which represents the balanced equation for the beta minus emission of phosphorus-32? Superscript 32 subscript 15 upper P right arrow superscript 28 subscript 13 upper A l plus superscript 4 subscript 2 upper H e. Superscript 32 subscript 15 upper P right arrow superscript 32 subscript 14 upper S i plus superscript 0 subscript negative 1 e. Superscript 32 subscript 15 upper P right arrow superscript 32 subscript 16 upper S plus superscript 0 subscript negative 1 e. Superscript 32 subscript 15 upper P right arrow superscript 32 subscript 14 upper S i plus superscript 0 subscript plus 1 e.

Answer 1

The answer is C

Step-by-step explanation:

Answer 2

`^(32)_(15)\textrm{P}\rightarrow ^(32)_(16)\textrm{S}+^0_(-1)\beta` represents the balanced equation for the beta minus emission of phosphorus-32.

Option C

Step-by-step explanation:

Given choices:

`^(32)_(15)\textrm{P}\rightarrow ^(28)_(13)\textrm{Al}+^2_(4)\textrm{He}`

`^(32)_(15)\textrm{P}\rightarrow ^(32)_(16)\textrm{Si}+^0_(-1)\beta`

`^(32)_(15)\textrm{P}\rightarrow ^(32)_(16)\textrm{S}+^0_(-1)\beta`

`^(32)_(15)\textrm{P}\rightarrow ^(32)_(14)\textrm{Si}+^0_(+1)\beta`

We need to find the balanced equation for the beta minus emission of phosphorus-32

Beta minus (β) is the decay process in which a neutron becomes a proton and releases beta particles, or better known as electrons. Means, atomic number gets increased by 1 (increasing one proton number).

So, from this concluding that in option C, Beta minus decay for phosphorus, it is replaced with sulfur core and increase in an atomic number (15 to 16). Hence, the balanced chemical equation for for the beta minus emission of phosphorus-32 is:

`^(32)_(15)\textrm{P}\rightarrow ^(32)_(16)\textrm{S}+^0_(-1)\beta`