Answer:
![9.45\cdot 10^(17)m](https://img.qammunity.org/2021/formulas/physics/college/ohqrhyxptk5f1clfynlym5j7uufp9gboaf.png)
Step-by-step explanation:
Radio waves are electromagnetic waves.
Electromagnetic waves travel in a vacuum at the speed of light, which is:
![c=3.0\cdot 10^8 m/s](https://img.qammunity.org/2021/formulas/chemistry/middle-school/dz068hai8fc255uekvuotgsus36jj1167k.png)
Therefore, the distance they cover in a time t is
![d=ct](https://img.qammunity.org/2021/formulas/physics/college/6sgw84yv0j22eyq04557p0urq6c372hh7p.png)
where d is the distance covered.
In this problem, the time elapsed is
t = 100 y
Keeping in mind that
![1y=365 d\cdot 24 h \cdot 60 m \cdot 60 s =3.15\cdot 10^7 s](https://img.qammunity.org/2021/formulas/physics/college/hludoblq8rvxm7oxf9mogi415uy4o916vs.png)
So the time elapsed in seconds is
![t=(100)(3.15\cdot 10^7)=3.15\cdot 10^9 s](https://img.qammunity.org/2021/formulas/physics/college/jd7ploup20uiqecln2gvkuzgjwm6g6bvej.png)
And therefore, the distance covered by the radio waves in this time is
![d=(3\cdot 10^8)(3.15\cdot 10^9)=9.45\cdot 10^(17)m](https://img.qammunity.org/2021/formulas/physics/college/tulz08y49owzoxnj8d5e2ah4z8n67ckbdg.png)