Question

find the density of seawater at a depth where the pressure is 280 atm if the density at the surface is 1035 kg/m^3. seawater has a bulk modulus of 2.3 x 10^9 N/m^2.

Answer 1

Step-by-step explanation:

Formula for Bulk modulus of a material is as follows.

B =
`(pV)/(\Delta V)`

(Bulk modulus = pressure × compressibility)

`(\Delta V)/(V) = (p)/(B)`

`(\Delta V)/(V) = 1 - (\rho)/(\rho')`

Hence,

`1 - (\rho)/(\rho') = (p)/(B)`

`1 - (1.03 * 10^(3))/(\rho') = (280)/(2.3 * 10^(9))`

`\rho'` =
`1.030 * 10^(3) kg/m^(3)`

Therefore, we can conclude that density of seawater at a depth where the pressure is 280 atm is
`1.030 * 10^(3) kg/m^(3)`.