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Need help with Question seven, on the topic of trigonometric functions.

Need help with Question seven, on the topic of trigonometric functions.-example-1
User WhoSayIn
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Answer:


\cos \: 2 \theta = (1)/(2) \\ \\ \therefore \: \cos \: 2 \theta = \cos \: 60 \degree \\ \therefore \: \cos \: 2 \theta = \cos \: (180 \degree - 120\degree ) \\ ( \because \: \theta \: lies \: between \: - 90 \degree \: and \: 90 \degree)\\ \therefore \: \cos \: 2 \theta = - \cos \: 120 \degree \\ \therefore \: 2 \theta = - 120 \degree \\ \therefore \: \theta = ( - 120 \degree)/(2) \\ \huge \red{\therefore \: \theta}\pink {= } \orange{ - 60 \degree}

User Gebitang
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