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Plz solve this question
Its urgent.....​

Plz solve this question Its urgent.....​-example-1
User Apostle
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Answer:

Explanation:

tan Θ + tan 2Θ + √3 tan Θ tan 2Θ = √3

tan Θ + tan 2Θ = √3 - √3 tan Θ tan 2Θ

tan Θ + tan 2Θ = √3 ( 1 - tan Θ tan 2Θ)

(tan Θ + tan 2Θ) / (1 - tanΘ tan 2Θ) = √3

tan(Θ + 2Θ) = √3

tan 3Θ = tan (
(\pi )/(3)) we know tan Θ = tan α; Θ = nΠ + α, n belongs to z

3Θ = nΠ + Π/3

Θ = nπ/3 + Π/9 for all n in Z

User Rotskoff
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