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4 votes
First Problem:

4. A six meter ladder leans against a building. The ladder makes an angle of elevation of 60° with the ground. How far up the
wall does the ladder reach?
Which trig formula should I use?

User Kmsquire
by
4.2k points

1 Answer

2 votes

Explanation:

Here,ladder is making a right triangle with the wall and ladder is acting as hypotenuse.

Angle of elevation formed between ladder and wall is 60°. Length of ladder is 6 m and we need to find the height (h) of the wall where ladder reaches.


\therefore \sin \: 60 \degree = (h)/(length \: of \: ladder) \\ \\ \therefore ( √(3) )/(2) = (h)/(6) \\ \\ \therefore h = ( √(3) )/(2) * 6 \\ \\ \therefore h = √(3) * 3 \\ \\ \therefore h = 3√(3) \\ \therefore h = 3 * 1.732 \\ \therefore h =5.196 \\ \therefore h \approx \: 5.2 \: m

Thus, ladder reaches upto a height of 5.2 m of the wall.

User SamHoque
by
4.7k points