Question

Arla and kal both work in jobs where they get paid by the hour in their first week on the job they each worked 40 hours and together

Answer 1

Question is Incomplete;Complete question is given below;

Arla and kal both work in jobs they get paid by the hour in their first week on the job they each worked 40 hours and together there total earnings were $1300 in their second week on the job business was slow so arla worked 20 hours and kal worked 16 hours their total pool earning was $580 what is each persons hourly wage.

Answer:

The hourly wage of Arla is $15 and hourly wage of Kal is $17.5.

Explanation:

Let the hourly wage of Arla be
`'x'`

Also Let the hourly wage of Kal be
`'y'`

Now Given:

first week on the job they each worked 40 hours and together there total earnings were $1300

So we can say that;

`40x+40y=1300` ⇒ equation 1

Also Given:

Number of hours worked by Arla in second week = 20

Number of hours worked by Kal in second week = 16

Total Money earned in second week = $580

So we can say that;

`20x+16y=580` ⇒ equation 2

Now Multiplying equation 2 by 2 we get;

`2(20x+16y)=580*2`

Applying Distributive property we get;

`40x+32y =1160` ⇒ equation 3

Now Subtracting equation 3 from equation 1 we get;

`(40x+40y)-(40x+32y)=1300-1160\\\\40x+40y-40x-32y=140\\\\8y=140`

Now Dividing both side by 8 we get;

`(8y)/(8)=(140)/(8)\\\\y= \$17.5`

Now Substituting the value of y in equation 1 we get;

`40x+40y=1300\\\\40x+40*17.5 =1300\\\\40x+700=1300\\\\40x=1300-700\\\\40x=600\\\\x=(600)/(40)\\\\x=\$15`

Hence The hourly wage of Arla is $15 and hourly wage of Kal is $17.5.