Answer:
the probability is 0.1087 (10.87%)
Explanation:
defining the random variable T= the test is positive , then the probability that the test is positive given that a bag is chosen at random is
P(T)= probability of choosing a bag with large amounts of liquid * probability that the test is positive given that that the bag have excess liquid + probability of choosing a bag that does not have not large amounts of liquid * probability that the test is positive given that that the bag does not have not have excess liquid = 1/100 * 0.97 + 99/100 * 0.1 = 0.1087 (10.87%)