Question

Derive the equation of the line that goes through (−3, 1) and (0, −5).

A
y=−2x

B
y=2x−5

C
y= −2x−5

D
y=2x+5

Answer 1

• (-3,1)
• (0,-5)

Slope:-

• m=-6/3=-2

Equation in point slope form

• y-1=-2(x+3)
• y-1=-2x-6
• y=-2x-5

Answer 2

C) y = -2x - 5

Explanation:

`\sf let \ (x_1,y_1)=(-3,1)\\\\let \ (x_2,y_2)=(0,-5)`

`\sf slope=(y_2-y_1)/(x_2-x_1)=(-5-1)/(0-(-3))=-2`

Point-slope formula:
`\sf y-y_1=m(x-x_1)`

`\sf \implies y-1=-2(x-(-3))`

`\sf \implies y=-2x-5`