154k views
1 vote
A man who moves to a new city sees that there are two routes he could take to work. A neighbor who has lived there a long time tells him Route A will average 5 minutes faster than Route B. The man decides to experiment. Each day he flips a coin to determine which way to go, driving each route 10 days. He finds that Route A takes an average of 48

?minutes, with standard deviation 44 minutes?,
and Route B takes an average of 49 minutes, with standard deviation 1 minute.
Histograms of travel times for the routes are roughly symmetric and show no outliers. Complete parts a and b. Use alpha?equals=0.05

User Sean L
by
8.5k points

1 Answer

3 votes

Answer:

0.3 to 2.3 min

Explanation:

n1=n2=10

x1=48

x2=49

s1=4

s2=1

Determine the deegres of freedom.


\delta=(((s_1^2)/(n_1)+(s_2^2)/(n_2))^2)/((((s_1^2)/(n1))^2)/(n_1-1)+(((s_1^2)/(n1))^2)/(n_2-1))=10.14

t=2.037 (student's appendix)


E=t\sgrt((s_1^2)/(n_1)+(s^2_2)/(n_2))=1.3


(x_1-x_2)-E=(48-49)-1.3=-2.3


(x_1-x_2)+E=(48-49)+1.3=0.3

We are 95% confident that average commuting time for rute A is between 0.3 and 2.3 min shorter than for rute B.

User Brian MacKay
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories