Answer:
I'll assume x is squared, case in which the function looks like this:
![f(x) = 10-x^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/n8hwzu541t93u35lhgl2yq705cu8ntut01.png)
The range is (-∞; 10] and be careful at those parentheses
Explanation:
You could, for example, think of what happens to x for different situations.
If x is very big,
is even bigger. 10 -
thus gets smaller, because you're subtracting something bigger and bigger. So, it tends to negative infinity.
Now, if x is any bigger than 10, it'll be a negative result, so
x>10 ==> f(x)<0
actually, this happens for any x>
![√(10)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/v9fk9je1zoywmssyv96nieje565m5yyay1.png)
For x negative, smaller (more negative) than -
, the result is the same.
If x is in the range
then the result becomes positive, since we're subtracting something smaller than 10. The biggest result we could ever achieve is when x=0. Thus 10 - 0 = 10.
In conclusion, 10 is the "upper limit" and -∞ is the "lower limit".
Thus, the range is (-∞ ; 10] AND BE CAREFUL AT PARENTHESES.